v^2+12v+20=(v+10)(v+)

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Solution for v^2+12v+20=(v+10)(v+) equation: 



v^2+12v+20=(v+10)(v+)

We move all terms to the left:

v^2+12v+20-((v+10)(v+))=0

We add all the numbers together, and all the variables

v^2+12v-((v+10)(+v))+20=0

We multiply parentheses ..

v^2-((+v^2+10v))+12v+20=0



We calculate terms in parentheses: -((+v^2+10v)), so:

(+v^2+10v)

We get rid of parentheses

v^2+10v

Back to the equation:

-(v^2+10v)



We add all the numbers together, and all the variables

v^2+12v-(v^2+10v)+20=0

We get rid of parentheses

v^2-v^2+12v-10v+20=0

We add all the numbers together, and all the variables

2v+20=0

We move all terms containing v to the left, all other terms to the right

2v=-20

v=-20/2

v=-10

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